x^2+4/5x-1/5=0

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Solution for x^2+4/5x-1/5=0 equation: 



x^2+4/5x-1/5=0



Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R



We calculate fractions


x^2=0

a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{2}=0$

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